Two examples
illustrated by Shane Baggs showing where the correction occurs.

The cube root of 27 is 3.

1. 1 | 1 | 27

2. 1 | 1 | 26

3. 2 | 1 | 26

4. 2 | 3 | 26

5. 4 | 3 | 26

6. 4 | 7 | 26

7. 4 | 7 | 19

8. 6 | 7 | 19 <=== Typo in the instructions occurs here

In step 8, instead of adding 2 as instructed in paragraph (f), add 1 as instructed in paragraph (e).

8. 5 | 7 | 19

9. 5 | 12 | 19

Now we add 2.

10. 7 | 12 | 19

11. 7 | 19 | 19

12. 7 | 19 | 0

It comes out even. Add 2 to the root number,

12. 7 + 2 = 9

and divide 9 by 3 to get 3, the answer.

13. 9 / 3 = 3

The cube root of 64 is 4.

1. 1 | 1 | 64

2. 1 | 1 | 63

3. 2 | 1 | 63

4. 2 | 3 | 63

5. 4 | 3 | 63

6. 4 | 7 | 63

7. 4 | 7 | 56

8. 6 | 7 | 56 <=== Typo in the instructions occurs here

In step 8 we should add 1, not 2.

8. 5 | 7 | 56

9. 5 | 12 | 56

Now add 2.

10. 7 | 19 | 56

11. 7 | 19 | 37

Now add 1.

12. 8 | 19 | 37

13. 8 | 27 | 37

Now add 2.

14. 10 | 27 | 37

15. 10 | 37 | 37

16. 10 | 37 | 0

17. 10 + 2 = 12

18. 12 / 3 = 4, which is the answer.

▪ *Abacus: Mystery of the Bead*

▪ *Advanced Abacus Techniques*

August,
2007