There are plenty of instruments out there that don't have unit rods marked on the beam. The following
techniques are one solution to solving the question, "Where should the decimal point go?"
Rule: Simplify both numbers to read x.xxx... Take the net of the decimal point movement in both the
multiplicand and in the multiplier. (This yields a number.) In the final analysis, undo by that number by
moving in the opposite direction. This is probably best explained in the following examples:
Example 1: 31.68 x 0.00082
Put both numbers in the form x.xxx .....
Move the decimal in the multiplicand one place to the left (call it L1).
Move the decimal in the multiplier four places to the right (call it R4).
This gives : 3.168 x 8.2
Take the net of these : L1 plus R4 = R3.
In the final analysis remember to *undo* R3 by moving the decimal point L3.
Now, look again at the equation : The approximation is 3 x 8 = 24
Undo R3 by moving the decimal point L3. This leaves 0.024
The actual answer to the problem is : 31.68 x 0.00082 = 0.0259776
Example 2: 5326.879 x 0.00000079
Put both numbers in the form x.xxx .....
Think : L3 for the multiplicand and R7 for the multiplier
5.326879 x 7.9
Take the net of these : L3 plus R7 = R4
Remember to "undo" R4 at the end by moving the decimal point L4.
The approx answer is 5 x 8 = 40
Undo R4 by moving the decimal point L4. This leaves 0.0040
The actual answer to to the problem is : 5326.879 x 0.00000079 = 0.004208234
Here's a method to consider for locating the decimal point in problems of division. The method is similar to that done for problems of multiplication in that we simplify both numbers to read x.xxx.... However, it's a little more complicated but once gotten used to it's very easy.
Rule: Simplify both numbers to read x.xxx... Take the net of the decimal point movement in the dividend and
the *opposite* of the decimal point movement in the divisor. (This yields a number.) In the final analysis,
undo by that number by moving in the opposite direction. Probably best explained by example. :)
Example 1: 0.68 ÷ 390
Put both numbers in the form x.xxx .....
Move the decimal in the dividend one place to the right (call it R1)
Move the decimal in the divisor two places to the left (call it L2)
The result is : 6.8 ÷ 3.9
Take the net of the decimal movement in the dividend and the *opposite* of the movement in the divisor. That is;
R1 plus R2 = R3
6.8 ÷ 3.9 is approximately 7 ÷ 4 = 1.75
Undo R3 by moving the decimal L3 : this equals 0.00175
The actual solution : 0.68 ÷ 390, is 0.00174358
Example 2: 0.073 ÷ 0.0054
Put both numbers in the form x.xxx .....
Think : R2 for the dividend and R3 for the divisor
The result is : 7.3 ÷ 5.4.
Take the net of the decimal movement in the dividend and the *opposite* of the movement in the divisor. That is;
R2 plus L3 = L1
7.3 ÷ 5.4 is approximately 7 ÷ 5 = 1.4
Undo L1 by moving the decimal R1 : this equals 14.00
Actual solution : 0.073 ÷ .0054 = 13.518...
Example 3: 897 ÷ 0.00061
Put both numbers in the form x.xxx .....
Think : L2 for the dividend and R4 for the divisor
8.97 ÷ 6.1
Take the net of the decimal movement in the dividend and the *opposite* of the movement in divisor. That is;
L2 plus L4 = L6
8.97 ÷ 6.1 is approximately 9 ÷ 6 = 1.5
Undo L6 by moving the decimal R6 : this equals 1500000.00
Actual solution : 897 ÷ 0.00061 = 1470491.803
Back to Multiplication
Back to Division
Back to Finding the Decimal
Gary Flom Atlanta Georgia USA
Email
gsflom[at]bellsouth[dot]net